Geometrie-Viereck-Gleichschenkliges Trapez

$A = \frac{a+c}{ 2}\cdot h$
1 2 3 4 5 6 7 8 9 10 11 12
$a = \frac{2\cdot A}{ h} - c$
1 2 3 4 5
$c = \frac{2\cdot A}{ h} - a$
1 2 3 4 5
$h = \frac{2\cdot A}{a+c}$
1 2 3 4 5
Beispiel Nr: 03
$\begin{array}{l} \text{Gegeben:}\\\text{Grundlinie c} \qquad c \qquad [m] \\ \text{Grundlinie a} \qquad a \qquad [m] \\ \text{Höhe} \qquad h \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{a+c}{ 2}\cdot h\\ \textbf{Gegeben:} \\ c=9m \qquad a=5m \qquad h=8m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{a+c}{ 2}\cdot h \\ c=9m\\ a=5m\\ h=8m\\ A = \frac{5m+9m}{ 2}\cdot 8m\\\\A=56m^{2} \\\\\\ \small \begin{array}{|l|} \hline c=\\ \hline 9 m \\ \hline 90 dm \\ \hline 900 cm \\ \hline 9\cdot 10^{3} mm \\ \hline 9\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline a=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline h=\\ \hline 8 m \\ \hline 80 dm \\ \hline 800 cm \\ \hline 8\cdot 10^{3} mm \\ \hline 8\cdot 10^{6} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline A=\\ \hline 56 m^2 \\ \hline 5,6\cdot 10^{3} dm^2 \\ \hline 5,6\cdot 10^{5} cm^2 \\ \hline 5,6\cdot 10^{7} mm^2 \\ \hline \frac{14}{25} a \\ \hline 0,0056 ha \\ \hline \end{array} \end{array}$