Beispiel Nr: 01
$ \text{Gegeben:}\\\text{Kreiszahl} \qquad \pi \qquad [] \\ \text{Fläche} \qquad A \qquad [m^{2}] \\ \text{Winkel} \qquad \alpha \qquad [^{\circ}] \\ \\ \text{Gesucht:} \\\text{Radius} \qquad r \qquad [m] \\ \\ r = \sqrt{\frac{A\cdot 360}{\alpha \cdot \pi }}\\ \textbf{Gegeben:} \\ \pi=3,14 \qquad A=5m^{2} \qquad \alpha=60^{\circ} \qquad \\ \\ \textbf{Rechnung:} \\ r = \sqrt{\frac{A\cdot 360}{\alpha \cdot \pi }} \\ \pi=3,14\\ A=5m^{2}\\ \alpha=60^{\circ}\\ r = \sqrt{\frac{5m^{2}\cdot 360}{60^{\circ} \cdot 3,14 }}\\\\r=3,09m \\\\ \tiny \begin{array}{|l|} \hline A=\\ \hline 5 m^2 \\ \hline 500 dm^2 \\ \hline 5\cdot 10^{4} cm^2 \\ \hline 5\cdot 10^{6} mm^2 \\ \hline 0,05 a \\ \hline 0,0005 ha \\ \hline 5\cdot 10^{-6} km^2 \\ \hline \end{array} \tiny \begin{array}{|l|} \hline alpha=\\ \hline 60 ° \\ \hline 3,6\cdot 10^{3} \text{'} \\ \hline 2,16\cdot 10^{5} \text{''} \\ \hline 66,7 gon \\ \hline 1,05 rad \\ \hline 0,00105 mrad \\ \hline \end{array} \tiny \begin{array}{|l|} \hline r=\\ \hline 3,09 m \\ \hline 30,9 dm \\ \hline 309 cm \\ \hline 3,09\cdot 10^{3} mm \\ \hline 3,09\cdot 10^{6} \mu m \\ \hline 0,00309 km \\ \hline \end{array}$