Beispiel Nr: 03
$ \text{Gegeben:}\\\text{Breite} \qquad b \qquad [m] \\ \text{Länge} \qquad a \qquad [m] \\ \\ \text{Gesucht:} \\\text{Diagonale} \qquad d \qquad [m] \\ \\ d = \sqrt{a^{2} +b^{2} }\\ \textbf{Gegeben:} \\ b=5m \qquad a=12m \qquad \\ \\ \textbf{Rechnung:} \\ d = \sqrt{a^{2} +b^{2} } \\ b=5m\\ a=12m\\ d = \sqrt{(12m)^{2} +(5m)^{2} }\\\\d=13m \\\\\\ \tiny \begin{array}{|l|} \hline b=\\ \hline 5 m \\ \hline 50 dm \\ \hline 500 cm \\ \hline 5\cdot 10^{3} mm \\ \hline 5\cdot 10^{6} \mu m \\ \hline 0,005 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline a=\\ \hline 12 m \\ \hline 120 dm \\ \hline 1,2\cdot 10^{3} cm \\ \hline 1,2\cdot 10^{4} mm \\ \hline 1,2\cdot 10^{7} \mu m \\ \hline 0,012 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline d=\\ \hline 13 m \\ \hline 130 dm \\ \hline 1,3\cdot 10^{3} cm \\ \hline 1,3\cdot 10^{4} mm \\ \hline 1,3\cdot 10^{7} \mu m \\ \hline 0,013 km \\ \hline \end{array}$