Beispiel Nr: 07
$ \text{Gegeben:}\\\text{Grundlinie c} \qquad c \qquad [m] \\ \text{Grundlinie a} \qquad a \qquad [m] \\ \text{Höhe} \qquad h \qquad [m] \\ \\ \text{Gesucht:} \\\text{Fläche} \qquad A \qquad [m^{2}] \\ \\ A = \frac{a+c}{ 2}\cdot h\\ \textbf{Gegeben:} \\ c=4m \qquad a=6m \qquad h=3m \qquad \\ \\ \textbf{Rechnung:} \\ A = \frac{a+c}{ 2}\cdot h \\ c=4m\\ a=6m\\ h=3m\\ A = \frac{6m+4m}{ 2}\cdot 3m\\\\A=15m^{2} \\\\\\ \tiny \begin{array}{|l|} \hline c=\\ \hline 4 m \\ \hline 40 dm \\ \hline 400 cm \\ \hline 4\cdot 10^{3} mm \\ \hline 4\cdot 10^{6} \mu m \\ \hline 0,004 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline a=\\ \hline 6 m \\ \hline 60 dm \\ \hline 600 cm \\ \hline 6\cdot 10^{3} mm \\ \hline 6\cdot 10^{6} \mu m \\ \hline 0,006 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline h=\\ \hline 3 m \\ \hline 30 dm \\ \hline 300 cm \\ \hline 3\cdot 10^{3} mm \\ \hline 3\cdot 10^{6} \mu m \\ \hline 0,003 km \\ \hline \end{array} \tiny \begin{array}{|l|} \hline A=\\ \hline 15 m^2 \\ \hline 1,5\cdot 10^{3} dm^2 \\ \hline 1,5\cdot 10^{5} cm^2 \\ \hline 1,5\cdot 10^{7} mm^2 \\ \hline 0,15 a \\ \hline 0,0015 ha \\ \hline 1,5\cdot 10^{-5} km^2 \\ \hline \end{array}$