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$ d= 2\cdot r $
$ r= \frac{d}{2} $
$ A = r^{2} \cdot \pi $
$ r = \sqrt{\frac{A}{\pi }} $
$ U = 2\cdot r\cdot \pi $
$ r = \frac{ U}{2\cdot \pi } $
Geometrie-Kreis-Kreis
$d= 2\cdot r$
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$r= \frac{d}{2}$
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$A = r^{2} \cdot \pi$
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$r = \sqrt{\frac{A}{\pi }}$
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$U = 2\cdot r\cdot \pi$
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$r = \frac{ U}{2\cdot \pi }$
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Beispiel Nr: 14
$\begin{array}{l}
\text{Gegeben:}\\\text{Radius} \qquad r \qquad [m] \\
\\ \text{Gesucht:} \\\text{Durchmesser} \qquad d \qquad [m] \\
\\ d= 2\cdot r\\ \textbf{Gegeben:} \\ r=\frac{5}{9}m \qquad \\ \\ \textbf{Rechnung:} \\
d= 2\cdot r \\
r=\frac{5}{9}m\\
d= 2\cdot \frac{5}{9}m\\\\d=1\frac{1}{9}m
\\\\\\ \small \begin{array}{|l|} \hline r=\\ \hline \frac{5}{9} m \\ \hline 5\frac{5}{9} dm \\ \hline 55\frac{5}{9} cm \\ \hline 555\frac{5}{9} mm \\ \hline 555555\frac{5}{9} \mu m \\ \hline \end{array} \small \begin{array}{|l|} \hline d=\\ \hline 1\frac{1}{9} m \\ \hline 11\frac{1}{9} dm \\ \hline 111\frac{1}{9} cm \\ \hline 1111\frac{1}{9} mm \\ \hline 1111111\frac{1}{9} \mu m \\ \hline \end{array} \end{array}$